Question

bu soruya acil bakar mısınız ? lütfen

Answer 1

Ответ:

√48= 4√3, √108= 6√3, √50=5√2

$\frac{4 \sqrt{3} + 6 \sqrt{3} }{5 \sqrt{2} } = \frac{10 \sqrt{3} }{5 \sqrt{2} } = \frac{2 \sqrt{3} }{ \sqrt{2 } } \\ \frac{ \sqrt{2 } \times \sqrt{2} \times \sqrt{3} }{ \sqrt{2} } = \sqrt{2} \times \sqrt{3 } \\ \sqrt{6}$

√6 :)

Answer 2

Ответ:

$\sqrt{6}.$

Пошаговое объяснение:

$\dfrac{\sqrt{48}+\sqrt{108} }{\sqrt{50} }=\dfrac{\sqrt{16\cdot3}+\sqrt{36\cdot3} }{\sqrt{25\cdot2} }=\dfrac{4\sqrt{3} +6\sqrt{3} }{5\sqrt{2} }=\dfrac{10\sqrt{3} }{5\sqrt{2} } =\dfrac{2\sqrt{3} }{\sqrt{2} }=\dfrac{(\sqrt{2})^2\cdot\sqrt{3} }{\sqrt{2} } =\sqrt{2}\cdot\sqrt{3}=\sqrt{2\cdot3}=\sqrt{6}.$