Question

Срочно срочно!!! Даю 60 баллов! По математике

Answer 1

Ответ:

1)

$y = ln^{4}({x}^{2} + 5x - 1)$

$y' = 4 ln^{3} ( {x}^{2} + 5x - 1 ) \times (ln( {x}^{2} + 5x - 1))' \times ( {x}^{2} + 5x - 1)'$

$y' = 4 ln^{3} ( {x}^{2} + 5x - 1) \times \frac{1}{ {x}^{2} + 5x - 1 } \times (2x + 5)$

2)

$\int \frac{dx}{ {(5x + 6)}^{3} } = \frac{1}{5} \times \frac{ {(5x + 6)}^{ - 2} }{ - 2} = \frac{1}{10 {(5x + 6)}^{2} }$

3)

$x + 1 = 0 \\ x = - 1$

$\int _{ - 1}^{0} (x + 1)dx = ( \frac{ {x}^{2} }{2} + x) | _{ - 1}^{0} = \frac{ {0}^{2} }{2} + 0 - ( \frac{ {( - 1)}^{2} }{2} + (- 1)) = 0 - ( \frac{1}{2} - 1) = - ( - \frac{1}{2} ) = \frac{1}{2} = 0.5$

Площадь 0,5 кв.ед.