Question

Помогите решить пожалуйста

Answer 1

$\frac{\frac{1}{8}:\frac{5}{16}+2,25\cdot0,8}{(2\frac{1}{48}-1\frac{55}{72}):3\frac{1}{12}}+3\frac{3}{5}=\frac{\frac{1}{8}\cdot\frac{16}{5}+1,8}{(\frac{97}{48}-\frac{127}{72}):\frac{37}{12}}+\frac{18}{5}=\frac{\frac{2}{5}+\frac{9}{5}}{\frac{37}{144}\cdot\frac{12}{37}}+\frac{18}{5}=\frac{\frac{11}{5}}{\frac{1}{12}}+\frac{18}{5}=\frac{132}{5}+\frac{18}{5}=30$

Answer 2

Ответ:

$\frac{\frac{1}{8} :\frac{5}{16}+2,25*0,8 }{(2\frac{1}{48} - 1\frac{55}{72}):3\frac{1}{12} } +3\frac{3}{5}=\frac{\frac{1*16}{8*5} +1,8}{(\frac{97}{48} - \frac{127}{72}):3\frac{1}{12} }+3\frac{3}{5} = \frac{\frac{2}{5} +\frac{18}{10} }{\frac{291}{144}-\frac{254}{144} :3\frac{1}{12}}+3\frac{3}{5} =\frac{\frac{4}{10}+\frac{18}{10} }{\frac{37*12}{144*37} }+3\frac{3}{5} = \frac{\frac{22}{10} }{\frac{1}{12} }+3\frac{3}{5} = (\frac{22}{10}:\frac{1}{12})+3\frac{3}{5} = \frac{22*12}{10*1}+3\frac{3}{5} =26,4+3,6$

26,4+3,6=30