Question

Разложите на множители
32n^4x-2n^2x

Answer 1

$32n^{4}x-2n^{2}x\\ 2n^{2}x(16n^{2}-1)\\ 2n^{2}x(4n-1)(4n+1) \\ otvet: 2n^{2}x(4n-1)(4n+1)$

Answer 2

$=2n^2x(16n^2-1)=2n^2x(4n-1)(4n+1).\\\star a^2-b^2=(a-b)(a+b)\star$