Question

-6*(10х-1)
12-(х+5)
14+(2х-4)
-2х*3у*(-1)
3(х+2) – 2(х+4)
Помогите решить

Answer 1

1) -6*(10x-1) = 0
-60x + 6 = 0
-60x = -6
60x = 6
x = 6/60
x = 1/10

2) 12-(x+5) = 0
12 - x - 5 = 0
7 - x = 0
-x = -7
x = 7

3) 14 + (2x-4) = 0
10 + 2x = 0
2x = -10
x = -5

5) 3(x+2) - 2(x+4) = 0
3x + 6 - 2x - 8 = 0
x - 2 = 0
x = 2