Question

A spring requires a load of 2.5 N to increase its
length by 4.0 cm. The spring obeys Hooke's law.
What load will give it an extension of 12 cm?

Answer 1

Ответ:

F=kx , k=F/x=2.5/4*10^-2=62,5 N/m, F=65,2*0,12=7,5 N

Объяснение: