Question

(-2 1/3)во второй степени Срочно​

Answer 1

$-2\frac{1}{3}^{2}=(-\frac{7}{3})^{2}=\frac{49}{9}=5\frac{4}{9}$

Answer 2

Ответ:

$\boxed{\ a^2=a\cdot a\ \ ,\ \ \Big(\dfrac{a}{b}\Big)^{k}=\dfrac{a^{k}}{n^{k}}\ }\\\\\\\\\Big(-2\dfrac{1}{3}\Big)^2=(-1)^2\cdot \Big(\dfrac{7}{3}\Big)^2=+1\cdot \dfrac{7^2}{3^2} =\dfrac{49}{9}=5\dfrac{4}{9}$