Question

Помогите пожалуйста срочно
(3x+4)(3x - 4)=
(2 - 5n)(5n+2)=
(9p+4a)(9p - 4a)=
(7c^2+ 4x)(4x - 7с^2) =
(5 - 6b^2)(5+6b^2)=
(0,8a^3 - 1)(0,8a^3 +1)=​

Answer 1

3z^2 -16
4-25n^2
81p^2-16a^2
16x^2 -49c^4
25 - 36b^4
0,64^9 -1

Answer 2

$(3x + 4)(3x - 4) = (3x) {}^{2} - 4 {}^{2} = 9x {}^{2} - 16$

$(2 - 5n)(5n + 2) = 4 - 25n {}^{2}$

$(9p + 4a)(9p - 4a) = (9p) {}^{2} - (4a) {}^{2} = 81p {}^{2} - 16a {}^{2}$

$(7c {}^{2} + 4x)(4x - 7c {}^{2} ) = 16x {}^{2} - 49c {}^{4}$