Question

исследовать функцию и построить график y=1/4 (x^3+3x^2)

Answer 1

Ответ:

$y = \frac{1}{4} ( {x}^{3} + {3x}^{2}) \\ 0 = \frac{1}{4}( {x}^{3} + {3x}^{2}) \\ \frac{1}{4}( {x}^{3} + {3x}^{2}) = 0 \\ \frac{1}{4} x {}^{3} + \frac{3}{4} {x}^{2} = 0$

$\frac{1}{4} {x}^{2} (x + 3) = 0 \\ {x}^{2} (x + 3) = 0 \\ {x}^{2} = 0 \: \: \: \: \: \: \: x + 3 = 0 \\ x_{1} = - 3 \\ x_{2} = 0$