Question

4х^2+ 28cy + 49y^2
(4x2 + 49y)
(2x + 7y)^2
(x + 7y)^2
(2x - 7y)^2

Answer 1

4х²+ 28cy + 49у²=(2х+7у)²

(4x² + 49y)²=16х⁴+392х²у+2401

(2x + 7y)²=4х²+ 28cy + 49у²

(x + 7y)²=х²+14ху+49у²

(2x - 7y)²=4х²-28ху+49у²