Question

розкладіть на множники:
(3b-5)²-49
(2x-3)²-(x+4)²​

Answer 1

(3b – 5)² – 49 = (3b – 5)² – 7² = (3b – 5 – 7)(3b – 5 + 7) = (3b – 12)(3b + 2) = 3(b – 4)(3b + 2)

(2x – 3)² – (x + 4)² = (2x – 3 – x – 4)(2x – 3 + x + 4) = (x – 7)(3x + 1)