Question

Даю 50 балов. Помогите, пж

Answer 1

$\displaystyle\bf 2x^{2} +3x-2<0\\\\ 2x^{2} +3x-2=0\\\\ D=3^{2} -4\cdot 2\cdot (-2)=9+16=25=5^{2} \\\\\\ x_{1} =\frac{-3-5}{4} =-\frac{8}{4} =-2\\\\\\ x_{2} =\frac{-3+5}{4} =0,5\\\\\\ 2x^{2} +3x-2=2(x+2)(x-0,5)\\\\ (x+2)(x-0,5)<0$

+ + + + + (-2) - - - - - (0,5) + + + + +

                  ////////////

$\displaystyle\bf Otvet:x\in(-2 \ ; \ 0,5)$