Question

Срочно помогите решить!!!

Answer 1

$\dfrac{4x(-10+9x)}{12}+\dfrac{-2-2(2+7x^2)-4(x+x^2)}{6}=3$

Раскроем скобки в числителях дробей:

$\dfrac{-40x+36x^2}{12}+\dfrac{-2-4-14x^2-4x-4x^2}{6}=3\\\\\\\dfrac{-40x+36x^2}{12}+\dfrac{-6-18x^2-4x}{6}=3$

Умножим обе части уравнения на 12:

$-40x+36x^2+2(-6-18x^2-4x)=36\\\\-40x+36x^2+2\cdot(-6)+2\cdot(-18x^2)+2\cdot(-4x)=36\\\\-40x+36x^2-12-36x^2-8x=36\\\\-48x-12=36\\\\-48x=36+12\\\\-48x=48\\\\x=\dfrac{48}{-48}\\\\x=-1$