Question

827. 1) |x – 4|= 2;
2) |y + 5|= 3;
3) |3+ x| = 1,5;
4) |7-y| = -2;
5) |x + 3| + 4 = 9;
6) |y – 2| + 8 = 5.

Answer 1

827. 1) |x-4|=2
x-4=2
x=6
x-4=-2
x=2
x₁=2; x₂=6
2) |y+5|=3
y+5=3
y=-2
y+5=-3
y=-8
y₁=-8; y₂=-2
3) |3+ x| = 1,5
3+x=1,5
x=-1,5
3+x=-1,5
x=-4,5
x₁=-4,5; x₂=-1,5
4) |7-y| = -2
x₁=-4,5; x₂=-1,5
5) |x + 3| + 4 = 9
|x+3|=9-4
|x+3|=5
x+3=5
x=2
x+3=-5
x=-8
x₁=-8; x₂=2
6) |y – 2| + 8 = 5
|y – 2| =5-8
Iy-2I=-3
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