Question

Решите систему уравнений

Answer 1

$\left\{{{\frac{x+4}{5}-\frac{y-1}{8}=1}\atop{\frac{x+2}{9}-\frac{y-3}{6}=\frac{2}{3}}}\right.\\\left\{{{x=\frac{3}{8}+\frac{5}{8}y}\atop{\frac{x+2}{9}-\frac{y-3}{6}=\frac{2}{3}}}\right.\\\frac{\frac{3}{8}+\frac{5}{8}y+2}{9}-\frac{y-3}{6}=\frac{2}{3}\\y=1\\x=\frac{3}{8}+\frac{5}{8}\cdot1\\x=1\\(x,y)=(1,1)\\\left\{{{\frac{1+4}{5}-\frac{1-1}{8}=1}\atop{\frac{1+2}{9}-\frac{1-3}{6}=\frac{2}{3}}}\right.\\\left\{{{1=1}\atop{\frac{2}{3}=\frac{2}{3}}}\right.\\(x,y)=(1,1)$

Answer 2

Ответ:

(1; 1)

Объяснение: