Question

3x^2-5x+7=1+3x+x^2



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Answer 1

$3x^2-5x+7=1+3x+x^2\\3x^2-5x+7-1-3x-x^2=0\\2x^2-8x+6=0\\x^2-4x+3=0\\x^2-x-3x+3=0\\x\cdot(x-1)-3(x-1)=0\\(x-1)\cdot(x-3)=0\\x-1=0\\\bold{x=1}\\x-3=0\\\bold{x=3}\\\underline{x_1=1}\\ \underline{x_2=3}$

Answer 2

3x^2 - 5x + 7 - 1 - 3x - x^2 = 0
2x^2 - 8x + 6 = 0 | :2
x^2 - 4x + 3 = 0
D = 4 -> корень = 2
x1,2= -4+-2 /2
x1 = 1
x2 = 3