Question

Помогите прошу умоляю!

Answer 1

Ответ:

$1\\1. (8-a)^2=8^2-8*2*a+a^2=64-16a+a^2\\2. (9+4m)^2=9^2+9*4*2*m+(4m)^2=81+72m+16m^2\\3. (3a-b)^2=(3a)^2-3*2*a*b+b^2=9a^2-6ab+b^2\\4. (3y+1)^2=(3y)^2+3*2*1*y+1^2=9y^2+6y+1\\5. (2k-5c)^2=(2k)^2-2*5*2*k*c+(5c)^2=4k^2-20kc+25c^2\\6. 52^2=(50+2)^2=50^2+2^2=2704\\2\\1.x^{2} -12x+36=(x-6)^2\\2. \frac{1}{25} m^{2} +4mn+100n^{2} = (\frac{1}{5}m+10n)^2\\ 3. 0,81p^{2} +0,72pq+0,16q^{2} =(0,9p+0,4q)^2$