Question

Простое уравнение способом подстановки

Answer 1

$\left \{ {{y=8+x} \atop {x^2-(8+x)^2=16}} \right.$

$\left \{ {{y=8+x} \atop {x^2-64-16x-x^2=16}} \right.$

$\left \{ {{y=8+x} \atop {-16x=16+64}} \right.$

$\left \{ {{y=8+x} \atop {-16x=80}} \right.$

$\left \{ {{y=8+(-5)} \atop {x=-5}} \right.$

$\left \{ {{y=3} \atop {x=-5}} \right.$

О т в е т. (-5;3)