Question

розклади на множники​

Answer 1

$8^{3n+1}-8^{2n-1}=(2^{3n+1}-2^{2n-1})\cdot(2^{6n+2}+2^{5n}+2^{4n-2})=(2^{3n+1}-2^{2n-1})\cdot(2^{6n+2}+32^{n}+2^{4n-2})$