Question

Задание 7. Помогите пж

Answer 1

Ответ:

a)

$F(x) = 4x - \frac{ {x}^{3} }{3} + c$

M (-3;10)

$4 \times ( - 3) - \frac{( - 3)^{3} }{3} + c = 10 \\ - 12 + 9 + c = 10 \\ - 3 + c = 10 \\ c = 13$

$F(x) = 4x - \frac{ {x}^{3} }{3} + 13$

б)

$F(x) = 2 \times \frac{ {x}^{2} }{2} + 9x = {x}^{2} + 9x + c$

M (1;-5)

${1}^{2} + 9 \times 1 + c = - 5 \\ 10 + c = - 5 \\ c = - 15$

$F(x) = {x}^{2} + 9x - 15$

в)

$F(x) = - \cos(x) + c$

$- \cos( \frac{\pi}{3} ) + c = \frac{1}{4} \\ - \frac{1}{2} + c = \frac{1}{4} \\ c = \frac{1}{4} + \frac{2}{4} \\ c = \frac{3}{4}$

$F(x) = - \cos( x ) + \frac{3}{4}$