Question

помогите решить пожалуйста

Answer 1

Ответ:

Пошаговое объяснение:

  #  1) ( x⁸ )' = 8x⁷ ;

3) ( x^(2/3))' = 2/3 x^(- 1/3 ) = 2/[3x^(1/3)] = 2/(3•³√x );

5) ( 1/x¹⁰ )' = ( x⁻¹⁰ )' = - 10x⁻¹¹ = - 10/x¹¹ ;

7) ( 1/⁸√x³ )' = [ x^(- 3/8)]' = - 3/8 *x^(- 11/8) = - 3/8 * 1/x^(11/8) =

  = - 3/( 8•⁸√x¹¹ ) = - 3/( 8x•⁸√x³ ) ;

9) [ (- 5x )³]' = 3 *(- 5x )² * (- 5x )' = - 15*(- 5x )² ;

11) [ ⁸√(- 5 + 2x) ]' = [ (2x - 5 )^(1/8) ]' = 1/8 *(2x - 5 )^(- 7/8) =

   = 1/[ 8•(2x - 5 )^(7/8)] = 1/( 8•⁸√x⁷ )