Question

Python y=(a/(cos(a)+1))+((a^2)/(cos^2(a)+1))...+((a^n)/(cos^n(a)+1))

Answer 1

Ответ:

#python

import math

a = float(input("a = "))

n = float(input("n = "))

i = 2

y = 0

while i < n:

   y += (a / (math.cos(a)+1)) + (pow(a,(i)) / (pow(math.cos(a),i)+1))

   i += 1

print("y =", y)