Question

Разложите на множители:
${x}^{2} - 1$
$27 + {a}^{3}$
$216 - {y}^{3}$
$\frac{1}{8} {a}^{3} + {b}^{3}$
${a}^{6} - 8$
${a}^{3} {b}^{3} - {c}^{3}$
${a}^{3} - {b}^{15} {c}^{18}$
$125 {c}^{3} {d}^{3} + 0.008 {b}^{3}$
$\frac{64}{729} {x}^{3} - \frac{27}{1000} {y}^{6}$
​

Answer 1

Ответ:

Объяснение:

1) =(x-1)(x+1)

2)=(3+a)(3²-3a+a²)=(3+a)(9-3a+a²)

3)=(6-y)(6²+6y+y²)=(6-y)(36+6y+y²)

4)=($\frac{1}{2}$a+b)(($\frac{1}{2}$)²a²-($\frac{1}{2}$)ab+b²)

5)=(a²-2)($a^{4}$+2a²+4)

6)=(ab-c)(a²b²+abc+c²)

7)=(a-$b^{5}c^{6}$)(a²+a$b^{5}c^{6}$+$b^{10} c^{12}$)

8)=(5cd+0.2b)(25c²d²-bcd+0.04b²)

9)=($\frac{4}{9}$x-$\frac{3}{10}$y²)($\frac{16}{81}$x²+$\frac{4}{9}$x$\frac{3}{10}$y²+$\frac{9}{100}$y²)