Question

А в восьмой-в в восьмой

Answer 1

$a^8-b^8=(a^4-b^4)(a^4+b^4)=(a^2-b^2)(a^2+b^2)(a^4+b^4)=\\=(a-b)(a+b)(a^2+b^2)(a^4+b^4)$

Answer 2

(a^8-b^8)=(a^4-b^4)(a^4+b^4)=(a^2-b^2)(a^2+b^2)(a^4+b^4)=(a-b)(a+b)(a^2+b^2)(a^4+b^4)