Question

Помогите решить я не нашёл ришения

Answer 1

б)   $\frac{x^{2}+4x+4 }{x+8}=0<=>\left \{ {{x^{2} +4x+4=0} \atop {x+8\neq 0}} \right. <=>\left \{ {{(x+2)^2=0} \atop {x\neq -8}} \right. <=>\left \{ {{x=-2} \atop {x\neq -8}} \right. <=>x=-2$

Ответ:  {-2}

в)  $\frac{(-2-x)(x-8,5)}{(x-3)(x+4)}=0<=>\left \{ {{(-2-x)(x-8,5)=0} \atop {(x-3)(x+4)\neq 0}} \right. <=>\left \{ {{x_1=-2;x_2=8,5} \atop {x\neq 3;x\neq -4}} \right. <=>$

 $<=>x_1=-2;x_2=8,5$

Ответ:  {-2;   8,5}

г)  $\frac{(x+7)^2(x-4)}{x-4}<=>\left \{ {{(x+7)^2(x-4)=0} \atop {x-4\neq 0}} \right. <=>\left \{ {{(x+7)^2=0;x-4=0} \atop {x\neq 4}} \right. <=>\left \{ {{x_1=-7;x_2=4} \atop {x\neq 4}} \right. <=>$

    <=>  {-7}

Ответ:  {-7}