Question

ПОМОГИТЕ ПЖ ДАЮ 30 БАЛОВ

Answer 1

$\displaystyle\bf\\\frac{3x^{2} -11}{8} =10-\frac{74-2x^{2} }{12} \\\\\\\frac{3x^{2} -11}{8}\cdot 24 =10\cdot 24-\frac{74-2x^{2} }{12} \cdot 24\\\\\\(3x^{2} -11)\cdot3=240-(74-2x^{2} )\cdot 2\\\\\\9x^{2} -33=240-148+4x^{2} \\\\\\9x^{2} -4x^{2} =92+33\\\\\\5x^{2} =125\\\\\\x^{2}=25\\\\\\x_{1} =-5 \ \ ; \ \ x_{2} =5$