Question

$log_{x} (2x^{2} -3x-4)=2$

Answer 1

Ответ:

$log_{x} (2x^{2} -3x-4)=2$

x є $(\frac{3+\sqrt{41} }{4}$; +∞);

$2x^{2} -3x-4=x^{2}$

$2x^{2} -3x-4-x^{2} =0$

$x^{2} +x-4x-4=0$

$x*(x+1)-4(x+1)=0$

$(x+1)*(x-4)=0$

x+1=0

x-4=0

x=-1

x=4

x=4