Question

7^ log 7 5 +log sqrt 7 ^ 49
​

Answer 1

Ответ:

= 9

Объяснение:

${7}^{ log_{7}5} + log_{ \sqrt{7} }49 = 5 + log_{ {7}^{ \frac{1}{2} } }49= 5 + (1 \div \frac{1}{2} ) \times log_{7} 49= 5 + 2 \times log_{7} {7}^{2} = 5 + 2 \times 2 \times log_{7}7 = 5 + 4 \times 1 = 9$