Question

Пжжжжалуйчта помогите

Answer 1

$\displaystyle\bf\\\Big(\frac{99}{40} \Big)^{7} \cdot\Big(\frac{10}{11} \Big)^{7} \cdot\Big(\frac{2}{9} \Big)^{7} =\Big(\frac{99}{40}\cdot\frac{10}{11}\cdot\frac{2}{9} \Big)^{7} =\Big(\frac{9\cdot 11\cdot 10 \cdot 2}{4\cdot 10 \cdot 11\cdot 9} \Big)^{7}=\\\\\\=\Big(\frac{1}{2} \Big)^{7} =\frac{1}{128}$