Question

пожалуста даю 50 балов ​

Answer 1

$\displaystyle\bf\\1)\\\\\sqrt{x} =6\\\\x=36\\\\\\2)\\\\\sqrt{x} -5=2\\\\\sqrt{x} =7\\\\x=49\\\\\\3)\\\\\sqrt{5x-6} =2\\\\(\sqrt{5x-6} )^{2} =2^{2} \\\\5x-6=4\\\\5x=10\\\\x=2$

$\displaystyle\bf\\4)\\\\2\sqrt{7x+4} -10=0\\\\2\sqrt{7x+4} =10\\\\\sqrt{7x+4} =5\\\\(\sqrt{7x+4} )^{2} =5^{2} \\\\7x+4=25\\\\7x=21\\\\x=3$