Question

решите срочно!!40 баллов!! ​

Answer 1

$\displaystyle\bf\\BD=\sqrt{AD\cdot CD}=\sqrt{16\cdot 25} =\sqrt{4^{2} \cdot5^{2} } =4\cdot 5=20\\\\AC=AD+CD=16+25=41\\\\AB=\sqrt{AC\cdot AD} =\sqrt{41\cdot 16}=4\sqrt{41} \\\\BC=\sqrt{AC\cdot CD} =\sqrt{41\cdot 25} =5\sqrt{41}$