Question

помогите математику ​

Answer 1

Ответ:

1

Пошаговое объяснение:

Answer 2

$\frac{ log_{6}(12) + log_{6}(3) }{2 log_{3}(6) - log_{3}(4) } = \frac{ log_{6}(36) }{ log_{3}(6 {}^{2} ) - log_{3}(4) } = \frac{ log_{6}(6 {}^{2} ) }{ log_{3}( \frac{6 {}^{2} }{4} ) } = \\ \\ = \frac{2}{ log_{3}(9) } = \frac{2}{ log_{3}(3 {}^{2} ) } = \frac{2}{2} = 1$