Question

Помоги решить ПЖ. 100 балов

Answer 1

$\frac{5x-4}{3} =\frac{7-x}{2} +\frac{3x+1}{6} \\\\\frac{5x-4}{3}=\frac{3(7-x)}{6} +\frac{3x+1}{6}\\\\\frac{5x-4}{3}=\frac{21-3x+3x+1}{6} \\\\\frac{5x-4}{3}=\frac{22}{6} \\\\6(5x-4)=22*3\\\\10x-8=22\\\\10x=30\\\\x=3$

$\frac{2-4x}{5} =\frac{1-2x}{3} -\frac{x+3}{4} \\\\\frac{2-4x}{5} =\frac{4(1-2x)}{12} -\frac{3(x+3)}{12}\\\\\frac{2-4x}{5}=\frac{4-8x}{12} -\frac{3x+9}{12} \\\\\frac{2-4x}{5}=\frac{4-8x-3x-9}{12}\\\\ \frac{2-4x}{5}=\frac{-11x-5}{12} \\\\12(2-4x)=5(-11x-5)\\\\24-48x=-55x-25\\\\55x-48x=-25-24\\\\7x=-49\\\\x=-7$

Answer 2

1)

$\frac{5x - 4}{3} = \frac{7 - x}{2} + \frac{3x + 1}{6} \\ \frac{5x - 4}{3} - \frac{7 - x}{2} - \frac{3x + 1}{6} = 0 \\ 2(5x - 4) - 3(7 - x) - (3x +1) = 0 \\ 10x - 8 - 21 + 3x - 3x - 1 = 0 \\ 10x = 8 + 21 + 1 \\ 10x = 30 \\ x = 3$

2)

$\frac{2 - 4x}{5} = \frac{1 - 2x}{3} - \frac{x + 3}{4} \\ \frac{2 - 4x}{5} - \frac{1 - 2x}{3} + \frac{x + 3}{4} = 0 \\ 12(2 - 4x) - 20(1 - 2x) + 15(x + 3) = 0 \\ 24 - 48x - 20 + 40x + 15x + 45 = 0 \\ - 48x + 40x + 15x = - 45 + 20 - 24 \\ 7x = - 49 \\ x = - \frac{49}{7} \\ x = - 7$