Question

Помогите пж 15 мин
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Answer 1

а) $\frac{3-\sqrt{3} }{\sqrt{3} } =\frac{(\sqrt{3})^{2} -\sqrt{3} }{\sqrt{x} 3} =\frac{\sqrt{3} (\sqrt{3}-1) }{\sqrt{3} } =\sqrt{3} -1$

б)$\frac{b-3}{b-2\sqrt{3} b+3} =\frac{(\sqrt{b} )^{2} -(\sqrt{3})^{2} }{(\sqrt{b})^{2} -2\sqrt{3} b+(\sqrt{3})^{2} } =\frac{(\sqrt{b}-\sqrt{3})*(\sqrt{b}+\sqrt{3}) }{(\sqrt{b}-\sqrt{3})^{2} } =\frac{\sqrt{b}+\sqrt{3}}{\sqrt{b}-\sqrt{3}}$