Question

а)sin 1000 градусов cos 250 градусов-cos 1000 градусов sin250 градусов
б) tg 1050 градусов​

Answer 1

Ответ:

$a)\ sin1000^\circ \cdot cos250^\circ -cos1000^\circ \cdot sin250^\circ =\\\\\star \ \ sina\cdot cos\beta -sin\beta \cdot cosa=sin(a-\beta )\ \ \star \\\\=sin(1000^\circ -250^\circ )=sin750^\circ =sin(2\cdot 360^\circ +30^\circ )=\\\\\star \ \ sin(k\cdot 2\pi +a)=sina\ \ \star \\\\=sin30^\circ =\dfrac{1}{2}$

$b)\ \ tg1050^\circ =tg(6\cdot 180^\circ -30^\circ )=\\\\\star \ \ tg(k\cdot 180^\circ -a)=tg(-a)=-tga\ \ \star \\\\=tg(-30^\circ )=-tg30^\circ =-\dfrac{\sqrt3}{3}$