Question

СРОЧНО ПОМОГИТЕ С 4 НОМЕРАМИ ПОЖАЛУЙСТА!!!!!​

Answer 1

1)

$0.5 \sqrt{8100} - \frac{1}{4} \sqrt{64} = 0.5 \times 90 - \frac{1}{4} \times 8 = 45 - 2 = 43$

2)

$\sqrt{0.49 \times 25} = 0.7 \times 5 = 3.5$

3)

$\sqrt{ {5}^{6} \times {2}^{2} } = \sqrt{ {( {5}^{3}) }^{2} } \times \sqrt{ {2}^{2} } = {5}^{3} \times 2 = 125 \times 2 = 250$

4)

$\sqrt{18} \times \sqrt{2} - \frac{ \sqrt{27} }{ \sqrt{3} } = \sqrt{9 \times 2} \times \sqrt{2} - \frac{ \sqrt{9 \times 3} }{ \sqrt{3} } = 3 \sqrt{2} \times \sqrt{2} - \frac{3 \sqrt{3} }{ \sqrt{3} } = 3 \times 2 - 3 = 6 - 3 = 3$

1)

${x}^{2} = 11$

$x = \sqrt{11}$

или

$x = - \sqrt{11}$

2)

${x}^{2} = - 49$

∅

3)

$\sqrt{x} = 81 \\ {( \sqrt{x)} }^{2} = {81}^{2} \\ x = 6561$

4)

$\sqrt{x} = - 1$

∅

1)

$2 \sqrt{3} + 5 \sqrt{12} - 3 \sqrt{27} = 2 \sqrt{3} + 5 \sqrt{4 \times 3} - 3 \sqrt{9 \times 3} = 2 \sqrt{3} + 5 \times 2 \sqrt{3} - 3 \times 3 \sqrt{3} = 2 \sqrt{3 } + 10 \sqrt{3} - 9 \sqrt{3} = 3 \sqrt{3}$

2)

$( \sqrt{32} - \sqrt{8} ) \sqrt{2} = \sqrt{32} \times \sqrt{2} - \sqrt{8} \times \sqrt{2} = \sqrt{64} - \sqrt{16} = 8 - 4 = 4$

3)

${( \sqrt{5} - 2)}^{2} = { \sqrt{5} }^{2} - 2 \times 2 \times \sqrt{5} + {2}^{2} = 5 - 4 \sqrt{5} + 4 = 9 - 4 \sqrt{5}$

4)

$( \sqrt{6} + 4 \sqrt{3} )( \sqrt{6} - 4 \sqrt{3} ) = { \sqrt{6} }^{2} - (4 \sqrt{3} ) {}^{2} = 6 - 16 \times 3 = 6 - 48 = 42$

1)

$3 \sqrt{7} \: \: < \: \: 4 \sqrt{6}$

2)

$5 \sqrt{ \frac{7}{5} } \: \: u \: \: \frac{1}{2} \sqrt{140} \\ \sqrt{ \frac{132}{5} } \: \: < \: \: \sqrt{ \frac{140}{4} }$