Question

2cos(7x-п/8)+корень2=0

Answer 1

Ответ:

{3п/56+2пk/7; -п/56+2пk/7: k - целое число}

Объяснение:

$2 \cos(7x - \frac{\pi}{8} ) + \sqrt{2} = 0 \\ 2 \cos(7x - \frac{\pi}{8} ) = - \sqrt{2} \\ \cos(7x - \frac{\pi}{8} ) = \frac{ \sqrt{2} }{2}$

7х-п/8 = п/4 + 2пk (1) или 7х-п/8 = -п/4 + 2пk (2)

1)

7х-п/8 = п/4 + 2пk

7х = 3п/8 + 2пk

х = 3п/56 + 2пk/7

2)

7х-п/8 = -п/4 + 2пk

7х = -п/8 + 2пk

х = -п/56 + 2пk/7