Question

задача по физике !!!

Answer 1

$T=2\pi \sqrt{LC}\\ \frac{T}{2\pi}=\sqrt{LC}\\ (\frac{T}{2\pi } )^{2} = LC\\C = \frac{T^2}{4\pi^{2} * L} \\C = \frac{4*10^{-12} }{4*3,14*3,14*4 * 10^{-3}*}= 25$пФ