Question

СРОЧНО!!! ДАЮ 60 БАЛЛОВ!!! (СМОТРИ СКРИН)

Answer 1

$\displaystyle\bf\\\\x^{2} +px+q=0\\\\x_{1,2} =-27 \ \pm \ \sqrt{729+7} =-27 \ \pm \ \sqrt{736} \\\\Teorema \ \ Vieta:\\\\-p=x_{1} +x_{2} =-27-\sqrt{736}-27+\sqrt{736} } =-54\\\\q=x_{1} \cdot x_{2} =(-27-\sqrt{736} )\cdot(-27+\sqrt{736} )=(-27)^{2} -(\sqrt{736})^{2} =\\\\=729-736=-7\\\\Otvet:1x^{2} +54x-7=0$