Question

1. tg4x=√3/3
2. cos3x=√2/2

Answer 1

ответ:

1. tg4x=√3/3⇒4x=arctg(√3/3)+πn⇒4x=

=π/6+πn⇒x== π/24+πn/4

2. cos(3x)=- (√2/2)3x=+-3п/4+2пк x=

=+-п/4+2пк/3