Question

Помогите пожалуйста, нужна 3 в четверти!!!

Answer 1

Ответ:

Объяснение:

S6 = b1 * (1 - q^6)/(1 - q)

а) b1 = 6, q = b2/b1 = 12/6 = 2

S6 = 6 * (1 - 2^6)/(1 - 2) = 6 * 63/1 = 378

б) b1 = 3, q = b2/b1 = (-0.6)/3 = -1/5

S6 = 3 * (1 - (-1/5)^6)/(1 - (-1/5)) = 3 * 0.999936/1.2 = 2.49984

в) b1 = 6, q = 6^2/6 6

S6 = 6 * (1 - 6^6)/(1 - 6) = 6 * 46655/5 = 9331

г) b1 = √3, q = 3/√3 = √3

S6 = √3 * (1 - √3^6)/(1 - √3) = √3 * 26/(√3 - 1) = 26 * √3 * (√3  + 1) / (3 - 1) =

= 26*(3  + √3)/2 = 13 * 3 + 13 * √3 = 39 + 13*√3