Question

Решите уравнение:
17x^2=20
22x^2=88

Answer 1

Ответ:

$17x {}^{2} = 20 \\ {x}^{2} = \frac{20}{17} \\ x = \pm \sqrt{ \frac{20}{17} } \\ - - - - - - \\ 22x {}^{2} = 88 \\ x {}^{2} = 88 \div 22 \\ x {}^{2} = 4 \\ x = \pm2$