Question

ПОМОГИТЕ
$-6+4x-5x^{2} =-9x^{2} -11x+13$

Answer 1

$\large \: x_1 = - \frac{19}{8} ,x_2 = 1$

Объяснение:

$- 6 + 4x - 5 {x}^{2} = - 9 {x}^{2} - 11x + 13$

$- 9 {x}^{2} - 11x + 13 + 6 - 4x + 5 {x}^{2} = 0$

${ - 4x {}^{2} - 15x +19 = 0}$

$\large\boxed{4x {}^{2} + 15x - 19 = 0}$

$D = {b}^{2} - 4ac \: \: \: \: \: \Rightarrow \: \: \: \: \: {15}^{2} - 4 \cdot4 \cdot( - 19)$

$D = 225 - ( - 304) = 529 \: \: \: \Rightarrow \: \: 15{}^{2} = \boxed{ 225} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - 4 \cdot 4 = \boxed{ - 16} \\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~16 \cdot( - 19 )= \boxed{ - 304}$

$\large \boxed{x_1,_2 = \frac{ - b\pm\sqrt{D \: } }{2a} }$

$\large \: \: x_1 = \frac{ - 15 - \sqrt{529} }{2 \cdot 4} = \frac{ - 15 - 23 }{ 8} = - \frac{38}{8} \: ~~~\Rightarrow~~~ \large \: \boxed{ - \frac{19}{8} }$

$\large \: x_2 = \frac{ - 15 + \sqrt{529} }{2 \cdot4} = \frac{ - 15 + 23}{8} ~~\Rightarrow~~\frac{8}{8} = \boxed{1}$

$\large \: \boxed{otvet:x_1 = - \frac{19}{8} ,x_2 = 1}$