Question

решите по рисунку 1 2 и 3 пожалуйста срочно

Answer 1

Ответ:

1)

а) 9⁸ × 9‐¹⁰ = 9‐² = (1/9)² = 1/81

б) 7‐⁹ : 7‐⁷ = 7-² = (1/7)² = 1/49

в) 9-⁶ : 3-¹² = 3-¹² : 3‐¹² = 1

2)

а)

$(x {}^{ - 6} ) {}^{3} \times x {}^{17} = x {}^{ - 18} \times x {}^{17} = x {}^{ - 1} = \frac{1}{x}$

б)

$\frac{x {}^{ - 5} - x {}^{ - 4} }{x {}^{ - 4} - x {}^{ - 3} } = \frac{ \frac{1}{x {}^{5} } - \frac{1}{x {}^{4} } }{ \frac{1}{x {}^{4}} - \frac{1}{x {}^{3} } } = \frac{ \frac{1 - x}{x {}^{5} } }{ \frac{1 - x}{x {}^{4} } } = \frac{1}{x}$

3)

$\frac{64 \times 25 {}^{ - 3} \times 14 {}^{ - 7} }{35 {}^{ - 6} } = \frac{64 \times 35 {}^{6} }{25 {}^{3} \times 14 {}^{7} } = \frac{64 \times 35 {}^{6} }{350 {}^{3} \times 14 {}^{4} } = \frac{64 \times 35 {}^{6} }{10 {}^{3} \times 35 {}^{3} \times 14 {}^{4} } = \frac{64 \times 35 {}^{3} }{10 {}^{3} \times 14 {}^{4} } = \frac{64 \times 35 {}^{3} }{140 {}^{3} \times 14 } = \frac{64 \times 35 {}^{3} }{14 \times 2 {}^{6} \times 35 {}^{3} } = \frac{32 \times 35 {}^{3} }{7 \times 2 {}^{6} \times 35 {}^{3} } = \frac{32}{7 \times 2 {}^{6} } = \frac{2 {}^{5} }{7 \times {2}^{6} } = \frac{1}{7 \times 2} = \frac{1}{14}$