Question

2х"2-х"2-8х+4=0 решите уравнение

Answer 1

корни

$x1 = 4 - 2 \sqrt{3}$

$x2 = 4 + 2 \sqrt{3}$

решение

$2x {}^{2} - x {}^{2} - 8x + 4 = 0$

$x {}^{2} - 8x + 4 = 0$

$a = 1$

$b = - 8$

$c = 4$

$x = \frac{ - ( - 8) + - \sqrt{( - 8) {}^{2} - 4 \times 1 \times 4} }{2 \times 1}$

$x = \frac{8 + - \sqrt{64 - 16} }{2}$

$x = \frac{8 + - 4 \sqrt{3} }{2}$

$x = 4 - 2 \sqrt{3}$

$x = 4 + 2 \sqrt{3}$