Question

Срочно, даю 100 балів.

Answer 1

$\displaystyle\bf\\1)\\\\-5 < -4 \ \ \ \Rightarrow \ \ f(-6)=x+6=-6+6=0\\\\\boxed{\boxed{f(-6)=0}}\\\\\\2)\\\\-4\leq -3,9 < 3 \ \ \ \Rightarrow \ \ \ \boxed{\boxed{f(-3,9)=8}}\\\\\\3)\\\\-4\leq 2 < 3 \ \ \ \Rightarrow \ \ \ \boxed{\boxed{f(2)=8}}\\\\\\4)\\\\3\geq 3 \ \ \ \Rightarrow \ \ \ f(3)=x^{2} =3^{2} =9\\\\\boxed{\boxed{f(3)=9}}\\\\\\5)\\\\5\geq 3 \ \ \ \Rightarrow \ \ \ f(5)=x^{2} =5^{2} =25\\\\\boxed{\boxed{f(5)=25}}$