Question

Способ алгебраического сложения решить систему уравнений (79-82)​

Answer 1

Ответ:

x = $4\frac{87}{89}$

y = $\frac{71}{89}$

Объяснение:

$\left \{ {{2x+\frac{x-y}{4} =11}|*4 \atop {3y-\frac{x-y}{3} =1}|*3} \right.$ $\left \{ {{8x+(x-y)=44} \atop {9y-(x-y)=3}} \right.$  $\left \{ {{8x+x-y=44} \atop {9y-x+y=3}} \right.$  $\left \{ {{9x-y=44} \atop {10y-x=3}|*9} \right.$   $\left \{ {{9x-y=44} \atop {90y-9x=27}} \right.$ ⇒

⇒ + $\left \{ {{9x-y=44} \atop {-9x+90y=27}} \right.$ $\left \{ {{9x-\frac{71}{89} =44} \atop {y=\frac{71}{89} }} \right.$  $\left \{ {{9x =44+\frac{71}{89}} \atop {y=\frac{71}{89} }} \right.$  $\left \{ {{x =44\frac{71}{89}*\frac{1}{9} } \atop {y=\frac{71}{89} }} \right.$  $\left \{ {{x =\frac{443}{89}} \atop {y=\frac{71}{89} }} \right.$ $\left \{ {{x =4\frac{87}{89}} \atop {y=\frac{71}{89} }} \right.$

             89y=71

                y=$\frac{71}{89}$