Question

решите пожалуйста!!!!!!​

Answer 1

$3\frac{1}{6} +(4\frac{5}{18}+1\frac{1}{2} )+\frac{7}{8} :\frac{3}{4} =10\frac{2}{18}\\\\1)4\frac{5}{18}+1\frac{1}{2}=\frac{77}{18} +\frac{3}{2} =\frac{77}{18}+\frac{27}{18} =\frac{104}{18} \\\\2)\frac{7}{8} :\frac{3}{4} =\frac{7}{8} *\frac{4}{3}=\frac{7*4}{8*3} =\frac{7}{6} \\\\3)3\frac{1}{6} +\frac{104}{18}+\frac{7}{6}=\frac{19}{6} +\frac{104}{18}+\frac{7}{6}=\frac{57}{18} +\frac{104}{18}+\frac{21}{18} =\frac{182}{18} =10\frac{2}{18}$