Question

помогите срочно дам 30 балів ​

Answer 1

а)

$(x+4)(x-4)=x^{2}-5x+9\\\\x^{2}-16-x^{2}+5x-9=0\\\\5x-25=0\\\\5x=25\\\\x=5$

б)

$(6-y)(y+6)=y^{2}-2y(y-3)\\\\36-y^{2}=y^{2}-2y^{2}+6y\\\\36-y^{2}+y^{2}-6y=0\\\\6y=36\\\\y=6$

в)

$8+9x(x+4)=(3x-2)(3x+2)\\\\8+9x^{2}+36x=9x^{2}-4\\\\9x^{2}+36x-9x^{2}=-4-8\\\\36x=-12\\\\x=-\frac{1}{3}$

г)

$2x(2x-4)-17=(5+2x)(2x-5)\\\\4x^{2}-8x-17=4x^{2}-25\\\\4x^{2}-8x-4x^{2}=17-25\\\\-8x=-8\\\\x=1$

Answer 2

Объяснение:

Вот, вроде правельно :3