Question

Здравствуйте ! Можете пожалуйста помочь?

Столбик А

Answer 1

${x}^{2} + 2xy + {y}^{2} = {(x + y)}^{2}$

$4 {x}^{2} + 4x + 1 = {(2x + 1)}^{2}$

$36 - 12a + {a}^{2} = {(6 - a)}^{2}$

$1 - 2a + {a}^{2} = {(1 - a)}^{2}$

$25 {a}^{2} + 10a + 1 = {(5a + 1)}^{2}$

$4 {x}^{2} + 12x + 9 = {(2x + 3)}^{2}$

$1 + {y}^{2} - 2y = {(1 - y)}^{2}$

$28xy + 49 {x}^{2} + 4 {y}^{2} = {(7x + 2y)}^{2}$

${m}^{4} + 2 {m}^{2} {n}^{3} + {n}^{6} = {( {m}^{2} + {n}^{3}) }^{2}$

$1 - 6 {c}^{2} + 9 {c}^{4} = {(1 - 3 {c}^{2} )}^{2}$

$100 {x}^{2} + {y}^{2} + 20xy = {(10x + y)}^{2}$

$- 28a + 4 {a}^{2} + 49 = {(2a - 7)}^{2}$

$4 {x}^{4} - 12 {x}^{2} {y}^{2} + 9 {y}^{4} = {(2{x}^{2} - 3 {y}^{2}) }^{2}$